Return true
if the string in the first element of the array contains all of the letters of the string in the second element of the array.
For example, ["hello", "Hello"]
, should return true
because all of the letters in the second string are present in the first, ignoring case.
The arguments ["hello", "hey"]
should return false
because the string hello
does not contain a y
.
Lastly, ["Alien", "line"]
, should return true
because all of the letters in line
are present in Alien
.
Solution 1
function mutation(arr) { let str1 = arr[0].toLowerCase(); let str2 = arr[1].toLowerCase(); let charCountsStr1 = _buildCharCounts(str1); for (let ch of str2) { if (str1.indexOf(ch) === -1) { return false; } } return true; } mutation(["hello", "hey"]);
Solution 2
function mutation(arr) { let str1 = [...arr[0].toLowerCase()]; let str2 = [...arr[1].toLowerCase()]; return str2.every(ch => { return str1.indexOf(ch) !== -1 }); }